[MWForum]transition form page to page

[Tony Wilson]

Dear All,
Does anyone know a way to move from page to page quickly (we are doing clay animation and I am hoping to run a quick slideshow on MW2)?
There may be many slides and I am looking for a quicker way of moving from page to page than
page1 wait 2 page2 wait 2 page3 wait 2 ..
Thanks
Tony.
Pavel Boytchev <pavel@elica.net> on Mon, 16 Feb 2004 03:15:00 +0200 wrote:
> > >In probing why the number of sides relates to the angles
> > >(having to add up to 360) what angles are refered to? I am
> > >wanting to know why this is so.
> 
> If you draw a polygon with N sides, the turtle should definitely turn N
> times. Because angles (orientation, turtle's heading) do not change
> during FORWARD movement, the final orientation will be the same as if
> the turtle only turns around (and does not move forward). So, if the
> turtle stays on one place and makes N turns to the left, and if the
> final orientation is the same as the initial one, then all turn angles
> should have a sum = 360. If the angles are the same, then each of them
> should be 360/N. Thus, the following code:
> 
> repeat :N [ fd 10 lt 360/:N]
> 
> will draw a square when N=4, and a pentagon when N=5, and the bigger the
> N is, the more circle-like the polygon is.
> 
> This is a simplification of a more general phenomena.
> 
> [1] The overall turn angle is not necessarily equal to 360 degrees. It
> can also be 360*K where K is integer number (0, 360, -360, 720,
> -720,...) So if the overall turn angle is 360 degrees, this is just the
> case when K=1
> 
> [2] If you have both left and right turns, you must convert all of them
> into only left, or into only right (by using that LT :A = RT 0-:A). When
> you calculate the total sum of angles (positive and negative angles),
> the result must be 360*K if the final orientation is the same as the
> initial one.
> 
> Pavel
> 
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---
Tony Wilson
Computer Coordinator
Holy Eucharist School
St Albans